Comparing to the last case, I tried an easier task this time.
Write a JavaScript function that retrieves the element with the largest font size in the current document, as calculated by CSS. It only needs to traverse down to 1/5 of the document’s height or at least 480px.
Bard with Gemini Pro gave a nice and clean answer with only code.
function findElementWithLargestFontSize() {
const maxTraversalHeight = Math.max(480, document.documentElement.clientHeight / 5);
let largestFontSize = 0;
let largestElement = null;
const traverseAndCheck = (element) => {
if (element.offsetTop > maxTraversalHeight) {
return; // Stop traversal if exceeded max height
}
const computedFontSize = parseFloat(window.getComputedStyle(element).fontSize);
if (computedFontSize > largestFontSize) {
largestFontSize = computedFontSize;
largestElement = element;
}
const childNodes = Array.from(element.childNodes);
childNodes.forEach(traverseAndCheck); // Traverse child nodes recursively
};
traverseAndCheck(document.body); // Start traversal from the body
return largestElement;
}GPT-4, as expected, gave a high quality answer with code and detailed explanation. Sometimes the text are inspiring, but cognitive load is increased obviously.
To create a JavaScript function that retrieves the element with the largest font size within a certain portion of a document, we need to take several steps. This function will traverse the DOM to find the element with the largest computed font size, considering a maximum depth determined by either 1/5 of the document’s height or at least 480px, whichever is larger. Here is a step-by-step approach to achieving this:
1. Calculate the maximum traversal depth based on the document’s height.2. Iterate through the elements within the specified portion of the document.
3. For each element, use `window.getComputedStyle()` to get the font size.
4. Compare the font sizes to determine the largest one.
5. Return the element with the largest font size.
Here’s how you can implement this:
function findElementWithLargestFontSize() {
const maxDepth = Math.max(document.documentElement.clientHeight / 5, 480);
let largestFontSize = 0;
let elementWithLargestFontSize = null;
function traverseElements(element, depth) {
if (depth > maxDepth) return;
const computedStyle = window.getComputedStyle(element);
const fontSize = parseInt(computedStyle.fontSize, 10);
if (fontSize > largestFontSize) {
largestFontSize = fontSize;
elementWithLargestFontSize = element;
}
for (let i = 0; i < element.children.length; i++) {
traverseElements(element.children[i], depth + element.children[i].offsetTop);
}
}
traverseElements(document.body, document.body.offsetTop);
return elementWithLargestFontSize;
}
// Example usage
const largestFontElement = findElementWithLargestFontSize();
console.log(largestFontElement);This function starts by defining the `maxDepth` to limit how deep into the document’s structure we search, based on the criteria given. It then defines a recursive function, `traverseElements`, that checks each element’s font size and updates the `largestFontSize` and `elementWithLargestFontSize` variables accordingly.
Note: This function assumes a relatively straightforward document structure. Complex layouts (e.g., with CSS transforms, absolute positioning, or iframes) might not be fully accounted for due to how they affect element offsets and actual visibility. Also, this function uses the `offsetTop` property to estimate the depth, which may not always accurately reflect visual document structure due to CSS styling. Adjustments may be needed based on specific document structures or requirements.
CodeLlama 70B is still disppointing. You may notice the point 2 that it mapped “at least” to “min”. Furthermore, It didn’t know the second sentence of the prompt is asked for higher efficiency than loop of all.
1. **Get the document’s height**
```javascript
const docHeight = document.documentElement.scrollHeight;
```
2. **Calculate the height to traverse**
```javascript
const traverseHeight = Math.min(docHeight / 5, 480);
```
3. **Get all elements in the document**
```javascript
const elements = document.getElementsByTagName(“*”);
```
4. **Initialize variables for the largest font size and corresponding element**
```javascript
let largestFontSize = 0;
let largestFontElement = null;
```
5. **Loop through elements and check font size**
```javascript
for (let i = 0; i < elements.length; i++) {
const element = elements[i];
const fontSize = parseFloat(window.getComputedStyle(element).fontSize);
if (fontSize > largestFontSize) {
largestFontSize = fontSize;
largestFontElement = element;
}
}
```
6. **Check if the element’s top position is within the traverse height**
```javascript
const elementTop = element.getBoundingClientRect().top;
if (elementTop > traverseHeight) {
break;
}
```
7. **Return the largest font element**
```javascript
return largestFontElement;
```
Here’s the complete code:
function getLargestFontElement() {
const docHeight = document.documentElement.scrollHeight;
const traverseHeight = Math.min(docHeight / 5, 480);
const elements = document.getElementsByTagName("*");
let largestFontSize = 0;
let largestFontElement = null;
for (let i = 0; i < elements.length; i++) {
const element = elements[i];
const fontSize = parseFloat(window.getComputedStyle(element).fontSize);
if (fontSize > largestFontSize) {
largestFontSize = fontSize;
largestFontElement = element;
}
const elementTop = element.getBoundingClientRect().top;
if (elementTop > traverseHeight) {
break;
}
}
return largestFontElement;
}This function will return the element with the largest font size in the current document, as calculated by CSS. It only traverses down to 1/5 of the document’s height or at least 480px.
CodeLlama 34B has the same min/max problem. Furthermore it failed to correlate element’s position with document’s height. But it’s smarter than 70B on the range of traversal.
Here is a JavaScript function that retrieves the element with the largest font size in the current document, as calculated by CSS:
function getLargestFontSize() {
const maxHeight = Math.min(document.documentElement.clientHeight, 480);
const maxDepth = Math.ceil(maxHeight / 5);
let largestFontSize = 0;
let largestFontSizeElement = null;
function traverse(element) {
if (element.nodeType === Node.ELEMENT_NODE) {
const fontSize = parseFloat(getComputedStyle(element).fontSize);
if (fontSize > largestFontSize) {
largestFontSize = fontSize;
largestFontSizeElement = element;
}
}
if (element.childNodes.length > 0 && element.clientHeight < maxHeight) {
for (let i = 0; i < element.childNodes.length; i++) {
traverse(element.childNodes[i]);
}
}
}
traverse(document.body);
return largestFontSizeElement;
}This function uses a recursive traversal algorithm to traverse down the document tree, starting from the `body` element. It checks the font size of each element using `getComputedStyle()` and updates the `largestFontSize` and `largestFontSizeElement` variables accordingly.
The function also keeps track of the maximum depth of the traversal using the `maxDepth` variable. If the depth of the traversal exceeds the maximum depth, the function stops traversing down that branch of the tree.
The function returns the element with the largest font size, or `null` if no element with a font size was found.
Note that this function only traverses down to 1/5 of the document’s height or at least 480px, as specified in the problem statement. If you want to traverse the entire document, you can remove the `maxHeight` and `maxDepth` variables and the corresponding checks in the function.
To address the min/max issue, i tried to revise the prompt to:
Write a JavaScript function that retrieves the element with the largest font size in the current document, as calculated by CSS. It only needs to traverse down to max(1/5 of the document’s height, 480px).
I paste only the final code by CodeLlama 70b. Maybe it’s aligned to spit a lot of intermediate steps like CoT to make the final part better but it shows no help in this case. As we found previously there are some fundamental problems.
function getElementWithLargestFontSize() {
const documentHeight = document.documentElement.scrollHeight;
const maxHeight = Math.max(documentHeight / 5, 480);
const elements = document.querySelectorAll('[style*="font-size"]');
const filteredElements = Array.from(elements).filter((element) => {
const rect = element.getBoundingClientRect();
return rect.top <= maxHeight;
});
const largestFontElement = filteredElements.reduce((largest, element) => {
const largestFontSize = window.getComputedStyle(largest).fontSize;
const elementFontSize = window.getComputedStyle(element).fontSize;
return largestFontSize >= elementFontSize ? largest : element;
});
return largestFontElement;
}We successfully correct it to use “max”, of course. Other problems stayed same and a new mistake on the element selector arose.
Like 70B, 34B was only able to correct the min/max mistake and made more other issues.
function getLargestFontSize() {
const maxHeight = Math.max(document.documentElement.clientHeight, 480);
const elements = document.querySelectorAll('*');
let largestFontSize = 0;
let largestFontSizeElement = null;
for (let i = 0; i < elements.length; i++) {
const element = elements[i];
const fontSize = parseFloat(getComputedStyle(element).fontSize);
if (fontSize > largestFontSize) {
largestFontSize = fontSize;
largestFontSizeElement = element;
}
}
return largestFontSizeElement;
}Try again.
function getLargestFontSize() {
const maxHeight = Math.max(document.documentElement.clientHeight / 5, 480);
let largestFontSize = 0;
let currentElement = document.body;
while (currentElement && currentElement.offsetTop < maxHeight) {
const fontSize = parseFloat(getComputedStyle(currentElement).fontSize);
if (fontSize > largestFontSize) {
largestFontSize = fontSize;
}
currentElement = currentElement.parentNode;
}
return largestFontSize;
}To my experience, the first answer of these smaller models for the same prompt is usually the best.
My almighty readers, could you suggest other paraphrase to make it work?
