My Nephew Brought Home This Menacing Maths Problem
Junaid Mubeen

One of your other entries has been linked to on Reddit. I am just browsing around. You write well and education is a topic about which I like to read so Kudos and thank you!

The problem and solution here are very interesting. May I suggest another solution?

The digits 1, 2, 3, and 4 arranged in any order will always result in a 4-digit number that has a remainder of 1 when divided by 3. The sum of 4 copies of these numbers will have a remainder of 1 when dividing by 3. Unfortunately 9000 is divisible by 3 or has a remainder of zero so the sum of the 4 copies cannot be 9000.

I wonder how close one can get to 9000 though. Food For Thought.

One clap, two clap, three clap, forty?

By clapping more or less, you can signal to us which stories really stand out.