Hope you have enjoyed my past series on 5 Question Series. In this article I am going to start the MCQs on basic Python, which contains 5 questions.

5 Question Series — Data Science & AI — 4

Q1. choose the incorrect option to get next week date from today?

1. pd.to_datetime((datetime.today() + timedelta(days = 7)).date()).strftime(‘%d %B %Y’)
2. pd.to_datetime(datetime.strptime(str(pd.to_datetime(‘today’).date()), ‘%Y-%m-%d’) + timedelta(days=7)).strftime(‘%d %B %Y’)
3. (datetime.now() + timedelta(days=7)).strftime(‘%d %B %Y’)
4. (datetime.today() + timedelta(days=7)).dt.date

Ans: d

Q2. choose the incorrect option for changing the day and hour from today’s datetime?

a) print(datetime.now().replace(day = 4, hour = 16))

b) (print(datetime.today().replace(day = 12, hour = 6))).dt.date

c) pd.to_datetime(‘today’).replace(day = 10, hour = 19)

d) pd.to_datetime(‘now’).replace(day = 10, hour = 19)

ans:b

Q3. ‘a’ is the series of random no. between some range. choose the correct option to change all the no. in the series in a string ‘python’ except the most repetitive no.?

a) a = pd.Series(np.random.randint(1,5,11))

a[~a.isin(a.value_counts().index[:1])] = ‘python’

b) a = pd.Series(np.random(1,5,11))

a[~a.isin(a.value_counts().index[:1])] = ‘python’

c) a = pd.Series(np.random.randint(1,5,11))

a[a.isin(a.value_counts().index[:1])] = ‘python’

d) a = pd.Series(np.random.randint(1:11:5))

a[a.isin(a.value_counts().index[:1])] = ‘python’

ans:a

Q4. from the given series: ‘movie’ and ‘rating’; choose the correct option to calculate the mean of ratings given to the movies?

movie = pd.Series(np.random.choice([‘Iron-Man’, ‘Spiderman’, ‘Deadpool’], 10)) rating = pd.Series(np.random.randint(1, 10, 10))

a) rating.groupby(movie).mean()

b) movie.groupby(rating).mean()

c) rating.groupby(movie).np.avg()

d) rating.groupby(‘movie’).mean()

ans :a

Q5.

# which is the correct option to plot the survival rate of ‘Pclass’ in titanic dataframe?

a) titanic.plot(‘Pclass’,’Survived’)

b) sns.barplot(‘Pclass’, ‘Survived’, data = titanic)

c) plt.bar(titanic, ‘Pclass’, ‘Survived’)

d) plt.bar(titanic[‘Pclass’],titanic[‘Survived’])

ans: b

Q6. choose the incorrect option to show the count of total survival and non-survival passengers in the dataframe ‘titanic’. Taking ‘Survived’ as 0 and ‘not_survived’ as 1?

survived = titanic[titanic[‘Survived’]==0]

not_survived = titanic[titanic[‘Survived’]==1]

a)print(“Survived: %i (%.1f%%)” % (len(survived), float(len(survived))/len(titanic)*100))

print(“Not_Survived: %i (%.1f%%)” % (len(not_survived), float(len(not_survived))/len(titanic)*100))

b)print(“Survived: %i (%.1f%%)” % (len(survived), (len(survived))/len(titanic)*100))

print(“Not_Survived: %i (%.1f%%)” % (len(not_survived), (len(not_survived))/len(titanic)*100))

c)print(“Survived: %i (%.1f)” % (len(survived), float(len(survived))/len(titanic)))

print(“Not_Survived: %i (%.1f)” % (len(not_survived), float(len(not_survived))/len(titanic)))

d) print(“Survived: (%.1f%%)” % (len(survived), float(len(survived))/len(titanic)*100))

print(“Not_Survived: (%.1f%%)” % (len(not_survived), float(len(not_survived))/len(titanic)*100))

ans:d

Hope you have liked these Questions, if any discrepancy or incorrect you feel here then please comment and do suggest some interesting questions and their solutions.

You can find my other series below:

5 Question Series — Data Science & AI — 3

5 Question Series — Data Science & AI — 2