Solving expected value and standard deviation for discrete distribution table by MyMathLab experts
About
This questions is about calculating the expected values and standard deviations for discrete distribution tables. Note that for discrete distributions, unlike normal distributions, values take specific values. A discrete distribution table is a way of representing the probability distribution of a discrete random variable. A discrete random variable is one that takes on a finite or countably infinite set of distinct values. The distribution table lists each possible value the random variable can take along with the corresponding probability of that value occurring. If you are searching for services related to paying someone to do mymathlab homework then you might have to seek additional tutorial services online.
Example question from discrete probability questions
For a group of four 50-year old men, the probability distribution for the number who live through the next year is as given in the table below.
Verify that the table is indeed a probability distribution. Then find the mean of the distribution.
Find the standard deviation of this probability distribution. Give your answer to at least 2 decimal places.
Discrete probability table solution
The first step in solving probability questions using a discrete distribution table is to check whether the probabilities add to 1. For the given case, the sum of the probabilities is 0.0001+0.0034+0.0469+0.2877+0.6619 = 1. Therefore, we can confirm that this meet meets the requirements of a probability distributions. Checking conditions for other distributions might be different, and so you might have to services related to mymathlab homework help in case you are interested in assessing distributions related to binomial, Poisson, and other types of probability distributions.
First calculated the Expected value of the distribution table using the formula; E(X) = sum(p*x);
Expected value = 0*0.0001 + 1*0.0034 + 2*0.0469 + 3*0.2877 + 4*0.6619 = 3.6079
The standard deviation for the table is the square root of sum(x² *p) — (e(x))²
0*0.0001 + 1*0.0034 + 4*0.0469 + 9*0.2877 + 16*0.6619 = 13.3707–3.6079² = sqrt(0.3537576) = 0.5948
