MySQL get all rows where id = xxx and where the newest column in other table in row with same id is greater than one

I have two mysql-tables: tbl_post and tbl_post_public

tbl_post looks like this:

id | post_id   |  author  |  date (unix time)
--------------------------------
 0 |  xxxxx1   | User1   |  1489926071
 1 |  xxxxx2   | User2   |  1489926075
 2 |  xxxxx3   | User3   |  1489926079

this table includes all posts by users

now I have the tbl_post_public table: this table contains the information, if the post of the user should be public. if the user changes from public to private, the row doesn't get updated. it just adds a new row with the same post_id but with a newer timestamp 0 = public | 1 = private

id | post_id | public | date (unix time)
    -----------------------------------------
 --> 0 |  xxxxx1 |  0     |  1489926071 <--| this two rows have the same
     1 |  xxxxx2 |  1     |                | post_id but the second is
     2 |  xxxxx3 |  0     |                | public = 1. I need to get 
 --> 3 |  xxxxx1 |  1     |  1489926099 <--| the second row because its newer
                    ^
                    |

so, in the result I want to have 10 Rows (LIMIT 10) ORDERED BY the date-column in tbl_post DESC WHERE author="User1" and WHERE the newest(date-column in tbl_post_public) row in tbl_post_public (which has the same post_id) and has public = 0