Generate the following two result sets:
- Query an alphabetically ordered list of all names in OCCUPATIONS, immediately followed by the first letter of each profession as a parenthetical (i.e.: enclosed in parentheses). For example:
AnActorName(A)
,ADoctorName(D)
,AProfessorName(P)
, andASingerName(S)
. - Query the number of ocurrences of each occupation in OCCUPATIONS. Sort the occurrences in ascending order, and output them in the following format:
There are a total of [occupation_count] [occupation]s.
- where
[occupation_count]
is the number of occurrences of an occupation in OCCUPATIONS and[occupation]
is the lowercase occupation name. If more than one Occupation has the same[occupation_count]
, they should be ordered alphabetically.
Note: There will be at least two entries in the table for each type of occupation.
Input Format
The OCCUPATIONS table is described as follows:
Occupation will only contain one of the following values: Doctor, Professor, Singer or Actor.
Sample Input
An OCCUPATIONS table that contains the following records:
Sample Output
Ashely(P)
Christeen(P)
Jane(A)
Jenny(D)
Julia(A)
Ketty(P)
Maria(A)
Meera(S)
Priya(S)
Samantha(D)
There are a total of 2 doctors.
There are a total of 2 singers.
There are a total of 3 actors.
There are a total of 3 professors.
SELECT CONCAT(NAME,’(‘,SUBSTR(OCCUPATION,1,1),’)’) AS N
FROM OCCUPATIONS
ORDER BY N;
SELECT CONCAT(‘There are a total of ‘,COUNT(OCCUPATION),’ ‘,LOWER(OCCUPATION),’s.’)
FROM OCCUPATIONS
GROUP BY OCCUPATION
ORDER BY COUNT(OCCUPATION), OCCUPATION;