Convert Any(CSV,JSON,XML) to XML in DWL

in this article I’m going to explain how can we convert Any(CSV,JSON,XML) to XML format, for that I build a DataWeave script to format any type of input(mentioned above) and any structure of input will convert into xml format.

it’s completely dynamic script there is no dependency of keys, values, type and structure of input.

%dw 2.0
output application/xml
/*
1.it will convert the any type/structure input to xml required format.
2.output of function anyToXml is in array format.
3.anyToXml accept two arguments like - anyToXml(arg1,arg2)
  1. arg1 indicates the payload
  2. arg2 indicates the type of payload
4.after exicution of anyToXml function our values come under root->rootItems->items
*/
fun anyToXml(inbound,dataType :String):Array =(
    if(lower(inbound.^mediaType) contains "xml") "root":"rootItems" : "item"  :inbound
    else if(inbound is Object)(
        if(dataType ~= "Object")
        "root":"rootItems" : "item"  : inbound
        else
        inbound
    )
    else if(inbound is Array) (
        "root":"rootItems" : inbound map(
            "item" : if($ is Object)
                        anyToXml($,"")
                     else anyToXml($,typeOf($))
        )
    )
    else if(dataType ~= "Object")
    inbound
    else "root":"rootItems" : "item": inbound
)
---
anyToXml(payload, typeOf(payload))

below are the snippets for different inputs

JSON -> XML

json(object) to xml

json(array) to xml

CSV -> XML

csv to xml

XML to XML

xml to xml

empty data to xml

empty string to xml

null to xml

single value to xml

any suggestions or comments or code issue(any format of input) please let me know so that I can improve the code