Using a simple program called Scan & Solve I ran some quick testing on the foundation footing to see which parts were under the most stress.

Numbers:

European Larch density = 590Kg / M^3

Cross sectional area of timber = 0.15m * 0.45m = 0.0675m^2

Lengths of timber range from 2m — 50m. I’ll assess the highest and lowest.

As the density of the Timber is 590Kg/ M^3 we just need the Volumes of timber.

2m lengths volume = 0.0675m^2 (CSA) * 2m = 71Kg

50m lengths volue = 0.0675m^2 (CSA) * 50m = 1788Kg

Converting Kg to N is awkward. F = ma should suffice, using gravity as the acceleration. The constant of that is 9.8 m/s^2

Newtons (2m) = 71kg * 9.8m/s^2 = 696.272N

Newtons (50m) = 1788kg * 9.8m/s^2 = 17541.645N

Final lap! Calculating Pascals.

Pa = N / M^2

(2m) — 696.272N / 0.0675m^2 = 10,315 Pa

(50m) — 17541.645N / 0.0675m^2 = 259,876 Pa

Now we can input some values into the stress tester.

After inputting those values into the stress tester the entire steel piece remained blue. So it works perfectly!

So here is it with the values cranked up a little to show some more definiton