HASH TABLE

Nidhikant
2 min readDec 4, 2022

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The Hash table data structure stores elements in key-value pairs where

  • Key- unique integer that is used for indexing the values
  • Value — data that are associated with keys.

Hashing (Hash Function)

In a hash table, a new index is processed using the keys. And, the element corresponding to that key is stored in the index. This process is called hashing.

Let k be a key and h(x) be a hash function.

Here, h(k) will give us a new index to store the element linked with k.

Hash Collision

When the hash function generates the same index for multiple keys, there will be a conflict (what value to be stored in that index). This is called a hash collision.

We can resolve the hash collision using one of the following techniques.

  • Collision resolution by chaining
  • Open Addressing: Linear/Quadratic Probing and Double Hashing.

1. Collision resolution by chaining

In chaining, if a hash function produces the same index for multiple elements, these elements are stored in the same index by using a doubly-linked list.

If j is the slot for multiple elements, it contains a pointer to the head of the list of elements. If no element is present, j contains NIL.

2. Open Addressing

Unlike chaining, open addressing doesn’t store multiple elements into the same slot. Here, each slot is either filled with a single key or left NIL.

Different techniques used in open addressing are:

i. Linear Probing

In linear probing, collision is resolved by checking the next slot.

h(k, i) = (h′(k) + i) mod m

where

  • i = {0, 1, ….}
  • h'(k) is a new hash function

If a collision occurs at h(k, 0), then h(k, 1) is checked. In this way, the value of i is incremented linearly.

The problem with linear probing is that a cluster of adjacent slots is filled. When inserting a new element, the entire cluster must be traversed. This adds to the time required to perform operations on the hash table.

ii. Quadratic Probing

It works similar to linear probing but the spacing between the slots is increased (greater than one) by using the following relation.

h(k, i) = (h′(k) + c1i + c2i2) mod m

where,

  • c1 and c2 are positive auxiliary constants,
  • i = {0, 1, ….}

iii. Double hashing

If a collision occurs after applying a hash function h(k), then another hash function is calculated for finding the next slot.

h(k, i) = (h1(k) + ih2(k)) mod m

NAME-NIDHIKANT

CLASS-BTECH CSE 3RD SEMESTER

ROLL NUMBER-22101137

SUBJECT-DATA STRUCTURES

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