Arduino Robotics Assignment 3

In today’s class, the first half of the class focused on arrays and functions , and the second half of the class Michael taught us how to do soldering.

I found there are so many similarities with JavaScript: the concepts of arrays, functions. But there are also some differences, such as to create a function, in Arduino, there is no “function” word ahead. Personally, I prefer the JavaScript way of creating a function, because it is more clear that it is a function.

Connect 3 LEDs to three non-adjacent pins (e.g. 3, 12, 7) on your Arduino. Make the LEDs blink in turn like you did in step #6 yesterday. Use for() loops and an array.

About the code:

creating a new array can be outside the loop and outside setup. But to define the elements in the loop in each line needs to be within the loop. And there is a more simple way below.

int foo[3];//foo is the name of the array
           //there are 3 elements in the array

void setup() {
}
void loop() {
  foo[0]=3;//the first pin is #3
  foo[1]=5;//the second pin is #5
  foo[2]=8;//the third pin is #8
  for(int i=0; i< 3; i++ ) {
    pinMode(foo[i], OUTPUT);
    digitalWrite(foo[i], HIGH); // turn the LED on (HIGH is the    voltage level)
    delay(1000); // wait for a second
    digitalWrite(foo[i], LOW); // turn the LED off by making the   voltage LOW
    delay(1000); // wait for a second
  }
}

int foo[3]={3,5,8};//create an array which has three elements:3,5,8
void setup() {
}
void loop() {
  for(int i=0; i< 3; i++ ) {
    pinMode(foo[i], OUTPUT);
    digitalWrite(foo[i], HIGH); // turn the LED on (HIGH is the    voltage level)
    delay(1000); // wait for a second
    digitalWrite(foo[i], LOW); // turn the LED off by making the   voltage LOW
    delay(1000); // wait for a second
  }
}

Write a function that turns off the three LEDs in problem #1, and modify your solution to problem #1 to use this function. In the loop, use the function to turn off all LEDs, then turn on only the one LED that should be on.

First Trial — -failed, the leds don’t turn off

The code:

int foo[3] ={3,5,8};

void turnOff(int i){  //the turnOff function
  pinMode(foo[i],OUTPUT);
  digitalWrite(foo[i], LOW);
}
void turnOn(int j){ //the turnOn function
  pinMode(foo[j],OUTPUT);
  digitalWrite(foo[j], HIGH);
}

void setup() {
}

void loop() {
  for(int h=0; h< 3; h++ ) {
    turnOn(h);
    turnOff(h+1);
    turnOff(h+2);
    delay(1000);
  }
}

Second Trial — — fail — — -all the leds are not turning on

int foo[3] ={3,5,8};

void turnOn(int j){
  pinMode(foo[j],OUTPUT);
  digitalWrite(foo[j], HIGH);
}
void turnOffAll(){
  pinMode(3,OUTPUT);
  digitalWrite(3,LOW);
  pinMode(5,OUTPUT);
  digitalWrite(5,LOW);
  pinMode(8,OUTPUT);
  digitalWrite(8,LOW);
}
void setup() {
}
void loop() {
  for(int h=0; h< 3; h++ ) {
  turnOn(h);
  turnOffAll();
  delay(1000);
}
}

Third trial — -succeed

int foo[3] ={3,5,8};

void turnOn(int j){
  pinMode(foo[j],OUTPUT);
  digitalWrite(foo[j], HIGH);
}
void turnOffAll(){
  pinMode(3,OUTPUT);
  digitalWrite(3,LOW);
  pinMode(5,OUTPUT);
  digitalWrite(5,LOW);
  pinMode(8,OUTPUT);
  digitalWrite(8,LOW);
}
void setup() {
}
void loop() {
  for(int h=0; h< 3; h++ ) {
  turnOn(h);
  delay(1000);
  turnOffAll();
 
}
}

A better version — — a loop within the turnOffAll() function.

int foo[3] ={3,5,8};

void turnOn(int j){
  pinMode(foo[j],OUTPUT);
  digitalWrite(foo[j], HIGH);
}

void turnOffAll(){
  for(int g=0;g<3;g+=1){
    pinMode(foo[g],OUTPUT);
    digitalWrite(foo[g],LOW);
  }
}
void setup() {
}
void loop() {
  for(int h=0; h< 3; h++ ) {
  turnOn(h);
  delay(1000);
  turnOffAll();
 
}
}