Taking Hash Tables Off The Shelf
Truth time: learning about theoretical things every week can get a bit monotonous. As much as it’s important to learn the method behind the madness, it’s equally crucial to understand why we’re embarking upon the path of madness to begin with it. In other words — what’s the point of the theory that we’re learning here together?
Sometimes, this can be a little tricky to illustrate. It’s hard to understand breadth first search if you don’t already know Big O notation. And Big O notation doesn’t mean anything to you unless you’ve seen it in action, in the context of an algorithm.
But every so often, we get lucky in that we stumble across the most perfect metaphor. Metaphors can be great way in of learning through analogy, and they’re useful in illustrating otherwise complicated concepts. I spent a few days trying to understand a data structure I was only recently introduced to, and it was only in the context of this metaphor that I really began to grasp it.
So, let’s see if we can unpack together.
Books on books on books
If you’ve moved across the country recently like I have, you probably have vivid memories of the horrors of trying to unpack everything. Or, maybe you’ve blocked it all out, in which case: well done! I was unpacking all of my books last week, and found myself sticking them all on the shelves rather haphazardly, without any order or logic behind which book went where.
I own a lot of books, sure, but I don’t have that many that it becomes difficult for me to find one. This got me thinking about libraries and their giant book collections, and how organized they actually have to be.
Imagine, for a moment, if all the libraries in the world didn’t organize or sort their books? Or, imagine if they were sorted by something super complicated…like by ISBN number?
We’re all better off because libraries are so methodically organized. But how did they come up with that? In fact, how does anyone come up with a good way of sorting through and finding an item within a large number of things?
Hopefully, a lightbulb just lit up in your head, and you’re thinking the same thing that I am: this is a computer science problem!
If we abstract this problem into programmatic terms, we can think of our book collection as our dataset. You can imagine that if we didn’t organize our books at all, there’s a good chance that we’d have to search through every single book on the shelf before we find the book that we’re looking for. And if we organized our books by ISBN number, or by the year that they were published, we’d still have to look through a subset of them, since it would still be a little difficult to find one item from amongst all the items on the shelf.
We’re already familiar with so many different data structures at this point — perhaps we can use one of them to handle our dataset? Let’s try them out for size.
How about using an array or a linked list?
Well, that would probably work fine in terms of holding all of our data. However, does this really solve our problem of searching through our dataset? Let’s think about it. In order to find a book using a linked list or an array, we’d still have to search through every single node in the worst case that the data that we were looking for was in the last node. This basically means that the time it takes for us to search through all of our books is directly related to how many books we have, which is linear time or O(n).
And what if we sorted our linked list, instead of adding in data randomly? Well, this would be a bit more helpful, since we could implement binary search on our linked list. Remember that we can apply binary search to any collection of sorted data, which is what we’d have in this case. We could split our large, sorted linked list or array into smaller sub-arrays, and narrow down for the book that we’re looking for. Even in the best case scenario, however, binary search would only ever let us reach logarithmic time, or O(log n). This would be nicer than linear time, of course, but still…none of these really seem like the most efficient way to search for a book.
It would be awesome if there was a way to just look up a book instantly — without having to search through everything. Surely, there must be a better way of doing this.
Mappings to make our lives easier
Okay, okay, we’re just learning about a cool data structure today — not inventing a new one! I guess I should finally let you in on the secret: there is a better way of searching through our dataset. And, as you might have guessed, it’s called a hash table.
Hash tables are made up of two distinct parts: an array, which you’re already familiar with, and a hash function, which is probably a new concept! So, why these two parts? Well, the array is what actually holds our data, and the hash function is more or less the way that we decide where our data will live — and how we’ll get it out of the array, when the time comes!
In the example above, we’re restructuring our bookshelf to be a hash map! Our shelves start off empty, and in order to add books (our data) to them, we pass the book into a hash function, which tells us which shelf to put it on.
Hash tables are interesting for a lot of reasons, but what makes them so efficient for our purposes is that they create a mapping, which is a relationship between two sets of data. Hash tables are made up of sets of pairs: a key and a value, often referred to as (k, v). The idea here is that if you have the key in one set of data, you can find the value that corresponds to it in another set of data.
In the case of a hash table, it is the hash function that creates the mapping. Since we’re working with arrays, the key is the index of the array, and the value is the data that lives at that index. The hash function’s job is to take an item in as input, and calculate and return the key for where that item should live in the hash table.
Alright: if we’re really going to sink our teeth into this topic, we’ll need an example. Let’s abstract out our bookshelf from earlier and simplify it further. In the example below, we’re looking at a hash table for book titles. The hash tables has its two predictable parts: an array, and a hash function.
Our hash table has a size of 12, which ultimately means that every single book needs to be stored somewhere within these twelve slots, which are also referred to as hash buckets.
Wait a second: how is that hash function deciding where to put those books!? If you take a closer look, you’ll notice that we’re using the modulo operator
%, which you might have already seen before. The modulo operator returns the remainder when one number is divided by another (or it returns 0, if the number can be divided evenly). So what is our hashing algorithm doing? Maybe you’ve already figured out the pattern here!
Our hash function takes the number of characters in the title, adds them up, and divides that summed total by the size of the table. For example,
"The Great Gatsby" has 14 characters in it (ignoring spaces), which, when divided by the 12, the size of the table, gives us a remainder of
2. So, our hash function will determine that
"The Great Gatsby" should live in the hash bucket with an index of
We can write out what our hash function would actually look like in code:
Alright, that’s simple enough! In fact, it’s almost…too simple. I feel like something’s going to go wrong now. Let’s keep going and see how far we can get with our hash function. We’ll try another book title:
"The Old Man and the Sea":
Oh no. I had a feeling this was going to happen!
When we input
"The Old Man and the Sea" into our hash function, it returns
6. This is bad because we already have a
"The Sound and the Fury” at hash bucket
6! That is bad, right?
Well, as it turns out, this isn’t bad at all. It’s actually quite normal. In fact, it’s so normal that this phenomenon even has a name: a collision, which occurs when two elements are supposed to be inserted at the exact same place in an array — in other words, at the same hash bucket.
What does this tell us about our hash function?
For starters, we can be sure that no hash function will always return a unique hash bucket value for every item that give it. In fact, a hash function will always input multiple elements to the same output (hash bucket), because the size of our dataset will usually be larger than the size of our hash table.
But why is this the case?
Super cool constant time
If we think more about hash tables in a practical context, it becomes pretty clear that we will pretty much always have multiple elements per hash bucket.
A good example of a hash table being applied to a real-world problem is a phonebook. A phonebook is massive, and contains all the data and contact information of every person that lives in a certain area.
How is it organized? By last name, of course. Each letter of the alphabet will have many people with that last name, which means that we’ll have many pieces of data at each letter’s hash bucket.
The hash function for a phonebook or a dictionary will always group any inputted data into one of 26 buckets — one bucket for each letter of the alphabet. This ends up being rather interesting, because what this effectively means is that we’ll never have a hash bucket (or in this case, a letter of the alphabet) that is empty. In fact, we’ll have close to an even distribution of last names that start with each letter of the alphabet.
In fact, that’s an important part of what makes a good hash algorithm: an equal distribution of data amongst all the possible hash buckets. But hold that thought for now — we’ll get more into that next week!
For now, let’s look at the other cool part about hash tables: their efficiency! Whether we’re dealing with a phonebook, a dictionary, or a library, the approach remains the same: our hash function will be what tells us where to put our data, and also where to get it out from!
Without using hash tables, we have to search through an entire dataset, probably starting with the first element in an array or linked list. If our items is at the very end of the list — well, good luck! We could be searching for a long time. In fact, as much time as there are elements! Herein lies the major problem with using linked lists, stacks, queues, arrays: searching through them for something always ends up being linear in time, or O(n).
Comparing this to hash tables, the choice between the two seems pretty easy, now that we understand how hash functions work! If we’re looking for an element, we need only to pass that element into the hash function, which will tell us exactly what index in the array — that is to say, which hash bucket — to look in. This means that even if the item we’re looking for is at the very end of the hash table array, it’ll take us the exact same amount of time to find it as it would for us to find the first element in the array!
No need to iterate through a massive list, or look through all the shelves in the library: we can look up our data quickly and easily, in constant time, or O(1). It also only takes constant time to insert or delete an item into a hash table, because we’re always going to lean on our hash function to determine where to add or remove something!
Algorithms and data structures that have a constant search time are super powerful. And, what’s more, they’re all around us. In fact, you might not even notice them. To bring it all back to where we started: think about how libraries organize things! Libraries around the world use the Dewey Decimal Classification System, which is really just a hash table with 10 buckets (and of course, a complex hash function that still I don’t quite understand yet).
Next week, we’ll dive deeper into hash functions and their collisions and discover how to resolve these conflicts, which are so common that there are entire algorithms for handling them. Try to resist the urge to reorganize your bookshelves until then!
I had a hard time narrowing down which resources to share with you because there are just so many of them! Which is not a bad problem to have. If you want to learn more about hash tables and how they work, check these links out.