LeetCode 412. Fizz Buzz

題目:

如例題: 3的倍數用Fizz代替，5用Buzz，同時是3跟5的倍數用FizzBuzz代替。

n = 15,

Return:
[
    "1",
    "2",
    "Fizz",
    "4",
    "Buzz",
    "Fizz",
    "7",
    "8",
    "Fizz",
    "Buzz",
    "11",
    "Fizz",
    "13",
    "14",
    "FizzBuzz"
]

思路:

1. result = []
2. for i in range(1, n+1):
   if i % 15 ==0:
   result.append(“FizzBuzz”)
   elif i %3 ==0:
   result.append(“Fizz”)
   elif i %5 ==0:
   result.append(“Buzz”)
   else:
   result.append(str(i))
3. return result

Coding:

class Solution:
    def fizzBuzz(self, n: int) -> List[str]:
        result = []
        for i in range(1, n+1):
            if i % 15 ==0:
                result.append("FizzBuzz")
            elif i %3 ==0:
                result.append("Fizz")
            elif i %5 ==0:
                result.append("Buzz")
            else:
                result.append(str(i))
        return result