# Problem:

Julia just finished conducting a coding contest, and she needs your help assembling the leaderboard! Write a query to print the respective hacker_id and name of hackers who achieved full scores for more than one challenge. Order your output in descending order by the total number of challenges in which the hacker earned a full score. If more than one hacker received full scores in same number of challenges, then sort them by ascending hacker_id.

Sample Output:

`90411 Joe`

Logic:

The output only have hacker_id and name, but Submissions table has only hacker_id while Hackers table has only name. So, we have to write a query to select hacker_id and name by joining Submissions table with Hackers, Challenges and Difficulty tables.

Next, filter the full score users by using s.score = d.score.

Then select count(*) > 1, group by h.hacker_id, h.name, and then order by count desc and hacker_id asc

Solution:

`select h.hacker_id, h.name from Submissions as s join Hackers as h on s.hacker_id = h.hacker_id join Challenges as c on s.challenge_id = c.challenge_idjoin Difficulty as d on c.Difficulty_level = d.Difficulty_levelwhere s.score = d.score group by h.hacker_id, h.name having count(*) > 1order by count(*) desc, h.hacker_id;`

Reference

--

--

--

## More from JEN-LI CHEN IN DATA SCIENCE

My homepage to record my thought processes for solving SQL and Algorithm questions

## Isabelle

In love with telling stories with data