80.remove-duplicates-from-sorted-array-ii
Detail explanation for updated two-pointer, runtime 93.73 %
Given a sorted array nums, remove the duplicates in-place such that duplicates appeared at most twice and return the new length.
Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.
Example 1:
Given nums = [1,1,1,2,2,3],Your function should return length = 5, with the first five elements of nums being 1, 1, 2, 2 and 3 respectively.It doesn't matter what you leave beyond the returned length.
Example 2:
Given nums = [0,0,1,1,1,1,2,3,3],Your function should return length = 7, with the first seven elements of nums being modified to 0, 0, 1, 1, 2, 3 and 3 respectively.It doesn't matter what values are set beyond the returned length.
Solution 1: updated two-pointer
This question is an updated version of question 26 (you should read this first). And the cracking method is basically the same. The only difference is that we need to start two pointers with index 2 and we only update nums[slow
when nums[fast] != nums[slow-2]
.