In this article certain questions have been randomly taken from different topics of the quantitative section of CAT. Each question has been selected keeping in mind certain challenges you need to manage as a test taker. These challenges may range from concept basics to application orientation and test taking strategies.

Grab the Unbelievable Offer:

= 2852.5+m(1.85-10x),which will be independent of m only if x=0.185; so T=2852.5

Now, number of males refusing bonus= 0.185m, which has to be a +ve integer

Therefore 185m/1000 is a +ve integer or 185/(1000/m) is a +ve integer. 1000/m =37 or 5. 37 not possible; so 1000/m=5, which gives m=200. Thus females=150. Bonus paid to females= 8.15*150=1222.5

Now, number of males refusing bonus= 0.185m, which has to be a +ve integer

Therefore 185m/1000 is a +ve integer or 185/(1000/m) is a +ve integer. 1000/m =37 or 5. 37 not possible; so 1000/m=5, which gives m=200. Thus females=150. Bonus paid to females= 8.15*150=1222.5

Approach :a flowers are for b rupees; and a+10 flowers are for 2 rupees

Therefore, b < 2 and since b is an integer, so b=1

(100/a) – (200/a+10)= 80/12

a = 5

Therefore, b < 2 and since b is an integer, so b=1

(100/a) – (200/a+10)= 80/12

a = 5

Approach :52231-49966=2265

2265 should be exactly divisible by the three digit number (if x=kn+m, y=ln+m, the remainder being m when x and y are divided by n, then x-y= n(k-l))

Now 2265 = 453*5

Thus n= 453

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Approach :Let the numbers be x and y

Then 4641*21 = x * y

Numbers can also be expressed as multiples of the HCF. Thus, x= 21a and y = 21b

Now 4641 * 21 = 21a * 21b

Or 13*17*21 *21= 21a *21b

Comparing LHS and RHS, a and b are 13*21 (=273) and 17*21(=357) in any order.

The answer is 357

Approach :225 = 9 * 25

For the number to be divisible by 225 it has to be divisible by both 9 and 25

For divisibility by 25, the last two digits should be zeroes or they should form a number which is multiple of 25. Hence we need 2 zeroes

For divisibility by 9, the sum of digits should be a multiple of 9. Only ones contribute to sum,and the least multiple of 9 is 9 itself; hence 9 ones

So, the number should have 9 ones and 2 zeroes or 11 digits