Print pattern ‘A’ in Python

Published in

programminginpython.com

3 min readJun 6, 2019

Hello everyone! Welcome back to programminginpython.com. I am continuing with this pattern programming series, here I will tell you how to print the pattern of the letter ‘A’.

Also, I will try to display the patterns for all other alphabets later in this series.

*Letter A — Pattern Programming — programminginpython.com*

Task:

Python program to print the pattern of letter ‘A’

Approach:

Read an input integer for asking the size of the letter using input()
Check if the entered number is greater than 8,
if yes, call the function print_pattern()
else, show a message to enter a number which is greater or equal to 8
print_pattern()
here we only do two things, print star(*) and print space( ), just writing conditions so the pattern of *‘s and ‘s will display the pattern ‘A’
following are 3 conditions for printing *’s
We have 2 loops, outer loop() for row’s and inner loop for columns.

     # Outer for loop
    for i in range(n): 
  
        # Inner for loop 
        for j in range((n // 2) + 1):

every line — at the start and end


(j == 0 or j == n //2) and i != 0

2. middle line — the whole line

i == n // 2

3. first line — whole line except first and last row

i == 0 and j != 0 and j != n // 2

print in remaining all cases.

Program:

__author__ = 'Avinash'# Python3 program to print alphabet A pattern# Function to display alphabet pattern 
def print_pattern(n): 
  
    # Outer for loop for number of lines(rows) 
    for i in range(n): 
  
        # Inner for loop for printing *'s and  &nbsp's(columns) 
        for j in range((n // 2) + 1): 
  
            # prints two column lines 
            if ((j == 0 or j == n //2) and i != 0 or
  
                # print first line of alphabet 
                i == 0 and j != 0 and j != n // 2 or
  
                # prints middle line 
                i == n // 2): 
                print("*", end = "") 
            else: 
                print(" ", end = "") 
          
        print()# Size of the letter
num = int(input("Enter the size: \t "))if num > 7:
    print_pattern(num)
else:
    print("Enter a size minumin of 8")

Output:

That’s it for this post guys, also feel free to check other programs on patterns here or find some programs on algorithms here.

Post: https://www.programminginpython.com/print-letter-a-pattern-python/