# Python Program to check Armstrong number or not

Hello readers, welcome back, here is an another simple python program which checks whether a number is an Armstrong number or not.

Generally, a number is said to be an Armstrong number if the sum of cubes of the digits is equal to its original number.

For Example : 153 is an Armstrong number as its sum of cubes of each digit 13 + 53 + 33 = 153 where as 456 is not as its sum of cubes of each digit is not 456.

#### Task :

Python program to check an integer number is an Armstrong number or not.

#### Approach :

- Read an input number using
`input()`

or`raw_input()`

. - Check whether the value entered is integer or not.
- Check input_num is greater than 0.
- Initialise a variable named
`arm_num`

to 0. - Find
`remainder`

of the input number by using mod (%) operator to get each digit in the number. - Now cube each digit and add it to
`arm_num`

. - Floor Divide the number by 10.
- Repeat steps 5. 6. 7 until the the input_num is not greater than 0.
- If
`input_num`

is equal to`arm_num`

, print number is ARMSTRONG. - When
`input_num`

is not equals to`arm_num`

, the number is NOT an Armstrong number.

#### Program :

input_num = (input("Enter any number: "))

try:

arm_num = 0

val = int(input_num)

while val > 0:

reminder = val % 10

arm_num += reminder ** 3

val //= 10

if int(input_num) == arm_num:

print(input_num, 'is an ARMSTRONG number')

else:

print(input_num, 'is NOT an armstrong number')

except ValueError:

print("That's not a valid number, Try Again !")

#### Output :

Post: http://programminginpython.com/python-check-armstrong-number/

**Python Programming - Check whether a number is Armstrong or not.**

*Hello readers, welcome back, here is an another simple python program which checks whether a number is an Armstrong…*programminginpython.com

GitHub: https://github.com/avinashn/programminginpython.com/blob/master/armstrong.py