# Python Program to check Armstrong number or not

Hello readers, welcome back, here is an another simple python program which checks whether a number is an Armstrong number or not.

Generally, a number is said to be an Armstrong number if the sum of cubes of the digits is equal to its original number.

For Example : 153 is an Armstrong number as its sum of cubes of each digit 13 + 53 + 33 = 153 where as 456 is not as its sum of cubes of each digit is not 456.

Python program to check an integer number is an Armstrong number or not.

#### Approach :

1. Read an input number using `input()` or `raw_input()`.
2. Check whether the value entered is integer or not.
3. Check input_num is greater than 0.
4. Initialise a variable named `arm_num` to 0.
5. Find `remainder` of the input number by using mod (%) operator to get each digit in the number.
6. Now cube each digit and add it to `arm_num`.
7. Floor Divide the number by 10.
8. Repeat steps 5. 6. 7 until the the input_num is not greater than 0.
9. If `input_num` is equal to `arm_num`, print number is ARMSTRONG.
10. When `input_num` is not equals to `arm_num`, the number is NOT an Armstrong number.

#### Program :

`input_num = (input("Enter any number: "))`
`try:    arm_num = 0    val = int(input_num)    while val > 0:        reminder = val % 10        arm_num += reminder ** 3        val //= 10`
`if int(input_num) == arm_num:        print(input_num, 'is an ARMSTRONG number')    else:        print(input_num,  'is NOT an armstrong number')`
`except ValueError:    print("That's not a valid number, Try Again !")`

#### Output :

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