# All Nodes on Any Matrix: The Same

*Differentiation shares a circle with integration.*

A node is a circle, because an intersection, is, a, circle. Any X and Y define, and, thus, conserve, a circle. Therefore, any node, on any matrix, is the same, as, any other node, on any other matrix (the nature of nature). (Differentiation shares a circle with integration.)

A technologist can see this. Others, not-so-much. You have to work with virtual reality (abstract reality) before you can understand reality (as a human experiences it).

Once you realize a node is a network (any object is a subject) (reality is asynchronous I/O) you have figured everything out. Left to you, then. What you want to do with it. What you want to do about it. (It is you.)