LeetCode 633. Sum of Square Numbers — JavaScript

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https://leetcode.com/problems/sum-of-square-numbers/description/?envType=daily-question&envId=2024-06-17

var judgeSquareSum = function(c) {
    const sqrt = Math.floor(Math.sqrt(c))
    for(let i=sqrt; i>=0;i--) {
        let tmp = c
        if(Math.sqrt(tmp-i*i) % 1 === 0) return true
    }
    return false
};

0 is the square of 0 and 0. if Math.sqrt(n)%1===0 means n is perfect square

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